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(A) $1$. Analyze the circuit: The circuit contains a short-circuit across one of the resistors. The wire connected in parallel to the resistor $R$ (in

Vedclass · Accepted Answer

$\frac{8R}{5}$

Vedclass · Answer

(A) $1$. Analyze the circuit: The circuit contains a short-circuit across one of the resistors. The wire connected in parallel to the resistor $R$ (indicated in the diagram) bypasses it,effectively removing it from the circuit.$2$. Simplify the circuit: After removing the shorted resistor,the remaining circuit consists of resistors arranged in a combination of series and parallel.$3$. Calculate equivalent resistance: The circuit reduces to a combination where the total resistance between $A$ and $B$ is calculated as $\frac{8R}{5}$.

What is the equivalent resistance between $A$ and $B$?

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